Flywheel Energy
E = ½Jω². Energy scales with the square of speed, so a small speed drop releases a lot. Sizing from a duty cycle: J = E/(Cs·ω²), where Cs is the allowed coefficient of speed fluctuation.
Inertia & stored energy
—
Inertia J
—
Energy released n₁→n₂
—
Tip speed
—
Required inertia from duty
Required J
—
Check burst margin — tip speed drives hoop stress. A helper, not a substitute for engineering judgment.